How do I set up a punnett square for sex linked?

The gene is sex-linked (on the X chromosome) and the ebony allele is dominant. You have a normal female and ebony male as the genotype of the parental generation.





How would I set up a F1 Punnett square and how would I find the expected F1 phenotypes (% of females and males) that are normal and ebony?





please explain. Thanks.

How do I set up a punnett square for sex linked?
Okie dokie...


When dealing with sex linked punnett squares, you have to remember that females have two copies of X and of course, males are XY. Also, dont forget that if the trait is sex linked, the male Y wont have any trait on it that you are worrying about.


We know that the female is normal. Since she isnt ebony (and ebony is dominant) we know that both her X chromosomes have the recessive allele (so you would put X with a little e in the top right corner): Xe Xe. The male is ebony so we know that his genotype would be XE Y (X with a big E in the top right corner). SO now cross Xe Xe with XE Y.





You wind up with 2 XE Xe and 2 Xe Y as your resulting genotypes. You should be able to tell phenotypes and % using that. Check the link for some visuals.
Reply:you doing flies right i had that to do that too